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Old 05-11-2008, 06:40 PM   #1 (permalink)
What should I put here?
 
Default Mathematical equation for the appropriate number of bikes to own

Trying to figure out how many bikes I should own and how many I have in my stable, this is what came to mind:

(X+1) = Y

Where X is the number of bikes currently owned, and Y is the appropriate number of bikes one should own.



Anyone got a formula for wheelsets?
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Old 05-11-2008, 06:42 PM   #2 (permalink)
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You sir, are a mathematical genius.
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Old 05-11-2008, 06:45 PM   #3 (permalink)
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x+2=y
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Old 05-11-2008, 07:01 PM   #4 (permalink)
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Default My formula

(X-1) + 2 = Y

Need to make room...

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Old 05-11-2008, 07:44 PM   #5 (permalink)
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x+3=y
29er=training bike
fr2000=trail
IH Sunday=
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Old 05-11-2008, 07:49 PM   #6 (permalink)
 
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ok heres my equation

E=MC2

E being the number of bicycles you want.
M being the amount of bicycles you own.
C being the Bicycles you would like to own.
2 is the squared, proving that no matter how many bikes you own, there is always that many more bikes you would like to own
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Old 05-11-2008, 10:11 PM   #7 (permalink)
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I thought X+1=Bionicon ?
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Old 05-11-2008, 10:26 PM   #8 (permalink)
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This is math related and I thought it was funny

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Better to be judged by 12 than carried by 6
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Old 05-11-2008, 11:17 PM   #9 (permalink)
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Quote:
Originally Posted by integradriv3r View Post
This is math related and I thought it was funny

that would be i
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Old 05-11-2008, 11:23 PM   #10 (permalink)
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Quote:
Originally Posted by Pickettt View Post
that would be i
Yeah but if you're dealing in the realm of real numbers then it doesn't exist which is why the cartoon is funny. I think that was last semester for me so I kind of put it in the back of my brain. Right now I'm concentrating on derivatives and integrals
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Old 05-12-2008, 08:07 AM   #11 (permalink)
RRRRRR UUUUUUU Readyyyyyy
 
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Bikulus for Dummies

One I've Solved
X + 1 = Y – A

X = current bikes
1 = new bike
Y = wrath of wife
A= skin off your a$$


One I'm Still Working On
T = P(a) + S + 1

T = Time
P(a) = how much “pre-sell” required for “acceptance” to buy new rig and not lose "benefits"
S= Current stable size
1 = New addition to aforementioned current stable

Something tells me second is not calculable (sp?)

j/k my wife "accomodates" my 3 rigs with a smile (usually )
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Old 05-12-2008, 01:42 PM   #12 (permalink)
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Via Occam's Razor (http://en.wikipedia.org/wiki/Occam%27s_razor):

Written in C...

if( bikes )
{
bikes++;
}
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Old 05-12-2008, 01:50 PM   #13 (permalink)
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El d00d has it.
The lyric "One is the loneliest number that you'll ever do" comes to mind. Can't have a lonely bike, I guess.
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Old 05-12-2008, 01:57 PM   #14 (permalink)
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Quote:
Originally Posted by hoovermd View Post
Via Occam's Razor (http://en.wikipedia.org/wiki/Occam%27s_razor):

Written in C...

if( bikes )
{
bikes++;
}
but, you have to start somewhere...

Code:
    while(++bikes);
Quote:
Originally Posted by GOGrannyGO View Post
El d00d has it.
The lyric "One is the loneliest number that you'll ever do" comes to mind. Can't have a lonely bike, I guess.
that was supposed to be the wheel formula...
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Old 05-12-2008, 02:00 PM   #15 (permalink)
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I try to explain to my wife:

"Just because I have an extra frame or two that I build up and tear down, those DON'T count as bikes. Those are potential bikes and should not be included in the total count of kinetic bikes because the don't move."
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Old 05-12-2008, 02:04 PM   #16 (permalink)
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Quote:
that was supposed to be the wheel formula...
Ain't math great?
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Old 05-12-2008, 02:09 PM   #17 (permalink)
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The number of bikes I have: e^0
Bikes I'd like to have: lim 2x/1 as x->inifinity

I'm bored at school.
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Old 05-12-2008, 02:25 PM   #18 (permalink)
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Default I'm bored with work

here's the C# version. i'm concerned you'll never get out of that one...

Code:
    public class Bike
    {
        private DateTime m_modelDt;

        public DateTime ModelDate
        {
            get { return m_modelDt; }
            set { m_modelDt = value; }
        }

        public Bike(DateTime modelDt)
        {
            m_modelDt = modelDt;
        }

        public TimeSpan GetAge()
        {
            return DateTime.Now.Subtract(m_modelDt);
        }

        public static int CalculatePerfectBikeCount()
        {
            bool needMoreBikes = true;
            IList<Bike> bikes = new IList<Bike>();
            TimeSpan maxAge = new TimeSpan(730, 0, 0, 0);
            bikes.Add(new Bike(DateTime.Now));
            while (bikes.Count > 0 || needMoreBikes)
            {
                bikes.Add(new Bike(DateTime.Now));
                foreach (Bike bike in bikes)
                    if (bike.GetAge() > maxAge)
                        bikes.Remove(bike); //sell bike
            }
            return bikes.Count;
        }
    }